I am with a group of five of my friends. A box contains 8 pieces each of milk chocolate, white chocolate, and dark chocolate. The box is passed around the six of us, with each person taking 4 pieces. Assume that each person chooses at random without replacement from the available pieces. I am the last person to whom the box is passed. Find the chance that I pick 4 dark chocolates. Possible Solution: The probability of picking 4 dark chocolates in the first pick is same as picking 4 dark chocolates in the last pick" the answer should be: 8/24 * 7/23 * 6/22 * 5/21 = 6.58E^-0.3 im ok?
i like that answer, yes
also compute via \[\frac{\binom{8}{4}}{\binom{32}{4}}\] but there is no reason to change your answer
A person is selected at random from a population that has the following characteristics: 65% of the people are men; the others are women 12% of the men are smokers 7% of the women are smokers a. Find the chance that the selected person is a non-smoker, given that the person is a man. b. Find the chance that the selected person is a woman who smokes. c. Find the chance that the selected person is a smoker. d. Given that the selected person is a smoker, what is the chance that the person is a woman? e. Find the chance that the selected person is a man or a non-smoker.
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