Estimate the area under f(x)=(1/4)x^3+1
From x=0 to x=6 using 3 rectangles and left hand sums. Enter you estimates here?
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OpenStudy (anonymous):
so basically riemann sums?
OpenStudy (anonymous):
I guess I am totally lost
OpenStudy (anonymous):
you want the area from x= 0 to 6
you want to estimate it by calculating the area of 3 rectangles
which means you need to divide 0 to 6 into 3 even parts
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
so the width of each rectangle will be?
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OpenStudy (anonymous):
so then like 0/3 are you meaning
OpenStudy (anonymous):
sorry that makes absolutely no sense, can you rewrite it?
OpenStudy (anonymous):
0/3=0 dividing 6 into three parts right maybe Im not getting it I am a little confused
OpenStudy (anonymous):
|dw:1366152103774:dw|
OpenStudy (anonymous):
oh ok gotcha
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OpenStudy (anonymous):
0 to 6 is the range,
if the width of the rectangle is 0, that would mean there would be no area
you're dividing the range of the graph into 3 equal widths
OpenStudy (anonymous):
so the width of each rectangle would be?
OpenStudy (anonymous):
it would be 0
OpenStudy (anonymous):
(6-0)/3 =?
OpenStudy (anonymous):
or 1
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OpenStudy (anonymous):
the width of each rectangle would be the total range divided by the number of parts
OpenStudy (anonymous):
2
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok then what
OpenStudy (anonymous):
now the graph im about to draw is not your graph, its just an example
|dw:1366152416177:dw|
example of left hand area