Estimate the area under f(x)=(1/4)x^3+1 From x=0 to x=6 using 3 rectangles and left hand sums. Enter you estimates here?
so basically riemann sums?
I guess I am totally lost
you want the area from x= 0 to 6 you want to estimate it by calculating the area of 3 rectangles which means you need to divide 0 to 6 into 3 even parts
ok
so the width of each rectangle will be?
so then like 0/3 are you meaning
sorry that makes absolutely no sense, can you rewrite it?
0/3=0 dividing 6 into three parts right maybe Im not getting it I am a little confused
|dw:1366152103774:dw|
oh ok gotcha
0 to 6 is the range, if the width of the rectangle is 0, that would mean there would be no area you're dividing the range of the graph into 3 equal widths
so the width of each rectangle would be?
it would be 0
(6-0)/3 =?
or 1
the width of each rectangle would be the total range divided by the number of parts
2
yes
ok then what
now the graph im about to draw is not your graph, its just an example |dw:1366152416177:dw| example of left hand area
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