find the equation of the locus of a point that moves so that its distance from the line 12x-5y-1=0 is always 1 unit.

Question

shubhamsrg · Answer

that'd be a line parallel to this line at a distance of 1 unit.
use the formula for distance of a point and line and equate that to 1
you should get 2 equations

anonymous · Answer

i need someone to show me all the steps

anonymous · Answer

Let the coordinates of unknown point be (h,k)
Distance of (h,k) from line 12x-5y-1=0 :
$$\left| \frac{ 12h-5k-1 }{ \sqrt{12^2+5^2} } \right|$$ = 1

gotcha ?

anonymous · Answer

thanks mate ! :)

anonymous · Answer

Welcome bro!

anonymous · Answer

i dnt get hw u know that u will get two answers ?

anonymous · Answer

There can be two such points.. !
If u take such a point, then there is another point which is mirror image of this point if you consider the line as the mirror.

anonymous · Answer

@yasmin95