Simplify completely: 4x^2+5x+3/x
Is it one whole fraction where (4x^2+5x+3) is the numerator? If it is, then this is how you're meant to simplify: Separate into three whole parts that corresponds to the three terms on the numerator: \[\frac{4x^2+5x+3}{x}=\frac{4x^2}{x}+\frac{5x}{x}+\frac{3}{x}\] Then simplify each fraction: \[\large =4x+5+\frac{3}{x}\]
how do i simplify a fraction? @Azteck
When you have a fraction such as this: \[\frac{4x^2}{x}\] It can be rewritten as this right?: \[\frac{4\times x\times x}{x}\]
so 4x?
or 16x?
@Azteck
I was asking you a yes or no question if you can read what I wrote above. I asked you whether you know that the fraction can be rewritten what I wrote above.
oh yea
@Azteck
So then if I take the 4x out of the numerator and put brackets around the resulting fraction, it can also be rewritten as this right? \[\large \frac{4\times x\times x}{x}=(\frac{4x \times x}{x})\] \[\large =4x(\frac{x}{x})\]
so what is it simplified?
@Azteck
4x^2 + 5x^2 + 3x?
WHy must you get ahead of yourself? I'm giving you simple steps to follow but you always have to leap ahead, then you hit a wall and ask me whether it's this. Let's just follow a simple road where you understand what you're doing step by step.
fin @Azteck
And you don't need to keep tagging my name. I'm already here.
fine
Okay, so what I said above, do you agree? Please be honest.
yup
So inside the brackets: \[\large \frac{x}{x}=1\] Correct?
yup
Then: \[\large 4x(1)=4x\] Right?
right
SO now: \[\large \frac{4x^2}{x}=4x\] Could you tell me what \[\large \frac{5x}{x}\] would equal to?
alli_bear22, are you there?
I'm waiting for your response.
yea srry hold on
5x?
Remember: \[\frac{4x^2}{x}=4x\] What would \[\frac{4x}{x}=?\]
4x or 8x
you cancel the like-terms. Do you know what like-terms are?
yea so it would just be 4
Yes!. So what would \[\frac{5x}{x}=?\]
5
Correct! So now you simplified the question. THat's basically all you need to do.
\[\frac{3}{x}\] can't be simplified any further, so it's just that.
so its 4+5+3x?
but i know im wrong because thats not an option
Umm... \[\frac{4x^2}{x}+\frac{5x}{x}+\frac{3}{x}=4x+5+\frac{3}{x}\]
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