Question

if the complex number Z lies on the circle |Z-2i| = 2sqrt(2) then find arg( (Z-2)/Z+2) ) ?

Answer 1

Omg.. Hate complex no. !

Answer 2

Unfortunately, I love complex no. :( :)

Answer 3

Carry on bro ! :D D:

Answer 4

Did I say that I know how to solve this question? :P , please wait, I am trying

Answer 5

@Yahoo! try to put : z = x + iy

Answer 6

then continue.

Answer 7

|Z-2i| = 2sqrt(2) is a circle with centre (0,2) and radius 2sqrt(2)///

Answer 8

and i think we have to do something with that..:)

Answer 9

I can say that : \(x^2 - y^2 + 4y = 12\)

Answer 10

\(x+iy = Z\)

Answer 11

hey guys ho is these character

Answer 12

LoL It's you @jamespatrick1071

Answer 13

U r Ryt @phi but i dont get u

Answer 14

\[|Z-2i| = 2\sqrt{2}\]

\[arg( \frac{Z-2}{Z+2} )=arg(z-2)-arg(z+2)\]