Question

differentiate (1+x^2)^0.5 and hence using integration by parts, show that:

Answer 1

\[\int\limits_{}^{}\frac{ x^3 }{ \sqrt{1+x^2} }dx = \frac{ 1 }{ 3 }(x^2 - 2)\sqrt{1+x^2} +C\]

Answer 2

So i've found the differential as \[\frac{ x }{ \sqrt{1+x^2} }\]

Answer 3

Let f'(x) be the differential you've worked out and g(x) be x^2.