Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

can anyone assist me verifing this identity? (sinx + tanx)/(cosx+1=tanx

OpenStudy (anonymous):

i started by multiplying the numerator and denominator by the conjugate of cosx+1 .... but it does not look right and i dont know what to do next @precal

OpenStudy (anonymous):

ok, I usually recommend to work with the more complex side first. I then recommend to change everything into sines and cosines.

OpenStudy (anonymous):

So, the tan function should be changed into sine over cosine

OpenStudy (anonymous):

Then you have a sinx + a sinx/cosx

OpenStudy (anonymous):

sinx + sinx/cosx that is.

OpenStudy (anonymous):

Then find a common denominator. (sinxcosx + sinx)/cosx.

OpenStudy (anonymous):

Following so far?

OpenStudy (anonymous):

I havn't started working with the cosx + 1 yet, but that is coming up shortly.

OpenStudy (anonymous):

@bfinn4 are you there?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!