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Chemistry 12 Online
OpenStudy (toxicsugar22):

what is the quanity of soluter NiCI2* 6H20 added to the solution in moles solid mass is 8.320 g solution volume is 250 ml

OpenStudy (anonymous):

mass of nickel chloride = (solid mass) * (FW of NiCl2 / FW of NiCl2.6H2O) because number of NiCl2 in mol = mass of NiCl2 / FW(NiCl2) So number of NiCl2 is really just: solid mass / (FW of NiCl2.6H2O) this is the quantity in mol of solute added. i am assuming they are asking for the molar concentration, then you find it by: molar concentration = (number of NiCl2 ) / (volume of solution)

OpenStudy (anonymous):

numbers to follow later.

OpenStudy (toxicsugar22):

BUT WHAT IS THE FORMULA WEIGHT OF NICI2*6H20

OpenStudy (toxicsugar22):

THANT IS WHAT I DONT UNDERSTND IS HOW TO CACULATE 6H20

OpenStudy (anonymous):

FW is the number of grams of a substance when you have a mol of them. it's the sum of the atomic weights of the atoms in the formula.

OpenStudy (anonymous):

give me a sec.

OpenStudy (toxicsugar22):

IS IT 237.69108

OpenStudy (toxicsugar22):

THAT IS WHAT iGOT

OpenStudy (anonymous):

yes

OpenStudy (toxicsugar22):

SO NOW WHAT

OpenStudy (anonymous):

about 237.6 grams per mol (of NiCl2.6H2O). now divide the solid mass by this number. this gives you the number of NiCl2.6H2O in mol

OpenStudy (toxicsugar22):

.03501

OpenStudy (toxicsugar22):

NOW HOW DO i FIND THE VOLUME OF THIS IN LITTERS

OpenStudy (anonymous):

the volume of the solution? you have it as 250 mL

OpenStudy (anonymous):

the "quantity" that the question asks for is the number of NiCl2 (solute) added, i am guessing.

OpenStudy (anonymous):

the number of NiCl2 is equal to the number of NiCl2.6H2O

OpenStudy (toxicsugar22):

SO HOW DO i FING THE LITTER

OpenStudy (toxicsugar22):

OR THE VOLUME

OpenStudy (anonymous):

the volume of the solution, it's 0.250 liter (not litter)

OpenStudy (anonymous):

they are not asking you for the volume of solute. they want the quantity (or the number of mol). i am guessing of course because i haven't seen the actual question.

OpenStudy (toxicsugar22):

OK

OpenStudy (toxicsugar22):

WHAT SI THE SOLUTION OF THE MOLARITY

OpenStudy (toxicsugar22):

WULLD IT BE 0.350/.250 * 1/ OVER IM STUCK

OpenStudy (toxicsugar22):

AM i ON THE RIGHT TRACK

OpenStudy (toxicsugar22):

CAN YOU PLEASE SHOW ME

OpenStudy (anonymous):

molarity, or molar concentration, is number of NiCl2 over the volume of solution. so it is (number of NiCl2) / (.250 L) the unit is mol per liter. that's all!

OpenStudy (toxicsugar22):

IS IT 324.51 / .250

OpenStudy (anonymous):

it's 0.0350 mol / .250 liter and it comes out to 0.14 mol per liter. try to verify this yourself.

OpenStudy (toxicsugar22):

OK GOT IT THANKS

OpenStudy (anonymous):

so it's (number of NiCl2) / (.250 L) = (number of NiCl2.6H2O) / .250 L = (8.320 grams / 237.59 grams per mol) / .250 L = 0.140 mol per liter

OpenStudy (anonymous):

the answer should have three sig figs, as in 0.140 not 0.14 (i know, it's a pain in the butt)

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