Question

How do I solve Solve 8^(x - 2) = 3?

Answer 1

\[8^{x-2}=3\]

Answer 2

Use logarithms

Answer 3

take log to base eight of both sides

Answer 4

so \[\log _{8}x-2=\log _{8}3\]?

Answer 5

almost

Answer 6

\[8^{x-2}=3\\\log _{8}8^{x-2}=\log _{8}3\\%{x-2}=\log _{8}3\]

Answer 7

yes. you do this because, the variable we are solving for is in the exponent and we have to bring it down. The opposite of exponentiation is logarithm!