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Mathematics 8 Online
OpenStudy (anonymous):

what is the remainder of a taylor series?

OpenStudy (amistre64):

it tends to be the average of the place you stopped at and the next value calculation; having to do with integration

OpenStudy (amistre64):

\[\sum_{1}^{\infty}f(n)x^n=S_n+\frac{\int R_n+\int R_{n+1}}{2}\]

OpenStudy (amistre64):

or is it half the difference?

OpenStudy (amistre64):

im thinking its along the lines of \[\sum_0x^n=x^0+x^1+x^2+x^3+R_4\] where the remainder cam be approximated with integration

OpenStudy (anonymous):

Actually I can't visualize it...

OpenStudy (amistre64):

is there a particular taylor you need to assess? or is this just a general query?

OpenStudy (anonymous):

Yes I need to give the taylor series of 3rdroot of x

OpenStudy (anonymous):

the 4 first terms

OpenStudy (anonymous):

and give the remainder after the 4th term

OpenStudy (amistre64):

cube root of x?

OpenStudy (amistre64):

have you determined the taylor for it yet?

OpenStudy (anonymous):

yes

OpenStudy (amistre64):

\[f(x)=x^{1/3}\\ f'(x)=\frac13x^{-2/3}\\ f''(x)=-\frac29x^{-5/3}\\ f''(x)=\frac{10}{27}x^{-7/3}\\ \] at x=1 these all form the coeffs of the taylor \[\frac{1}{1},\frac13,-\frac{1(2)}{9},\frac{1(2)(5)}{27},-\frac{1(2)(5)(7)}{36}\] what did you get for the taylor?

OpenStudy (anonymous):

\[f \prime \prime \prime \prime (x)=\frac{ 10 }{ 27}x ^{-8/3}\]

OpenStudy (anonymous):

otherwise i get the same for the derivatives

OpenStudy (anonymous):

and I don't substitute one into x... i keep the x like that

OpenStudy (amistre64):

you have to sub in a value to x (say x=a) to define the coeffs of the taylor series with a variable (x-a)^n

OpenStudy (amistre64):

might not have that exactly recalled, but the derivatives define a sequence for the coeffs of the taylor

OpenStudy (amistre64):

the series representation of cbrt(x) applies a binomial calculation ... 1/3 C n

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