what is the remainder of a taylor series?
it tends to be the average of the place you stopped at and the next value calculation; having to do with integration
\[\sum_{1}^{\infty}f(n)x^n=S_n+\frac{\int R_n+\int R_{n+1}}{2}\]
or is it half the difference?
im thinking its along the lines of \[\sum_0x^n=x^0+x^1+x^2+x^3+R_4\] where the remainder cam be approximated with integration
Actually I can't visualize it...
is there a particular taylor you need to assess? or is this just a general query?
Yes I need to give the taylor series of 3rdroot of x
the 4 first terms
and give the remainder after the 4th term
cube root of x?
have you determined the taylor for it yet?
yes
\[f(x)=x^{1/3}\\ f'(x)=\frac13x^{-2/3}\\ f''(x)=-\frac29x^{-5/3}\\ f''(x)=\frac{10}{27}x^{-7/3}\\ \] at x=1 these all form the coeffs of the taylor \[\frac{1}{1},\frac13,-\frac{1(2)}{9},\frac{1(2)(5)}{27},-\frac{1(2)(5)(7)}{36}\] what did you get for the taylor?
\[f \prime \prime \prime \prime (x)=\frac{ 10 }{ 27}x ^{-8/3}\]
otherwise i get the same for the derivatives
and I don't substitute one into x... i keep the x like that
you have to sub in a value to x (say x=a) to define the coeffs of the taylor series with a variable (x-a)^n
might not have that exactly recalled, but the derivatives define a sequence for the coeffs of the taylor
the series representation of cbrt(x) applies a binomial calculation ... 1/3 C n
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