Question

Six letters are picked. Find the chance that they can be arranged to form the word RANDOM.

Answer 1

1 out of 26^6

Answer 2

Here its:
Note that the total possible number of rearrangements in RANDOMNESS is 6!=(6*5*4*3*2*2*1)=720, so, noting that we could get any of the one rearrangements from any of the 26^6 possible solutions, multiplying by the permutations gives us the probability of the favorable cases. Hence:
P((B) of rearrangements in RANDOMNESS is )=(( (1/26)^6)*6!= ((1/26)^6)*720 You are Done!!

Answer 3

yes got it grand