Question

solve for this

Answer 1

\[3| 3x-5|\ge66\]

Answer 2

3|3x-5|>=66

Answer 3

i'm not sure if it's [9,infinity)U(-infinity,-17/3]

or [9,1-7/3]

Answer 4

@ParthKohli

Answer 5

\[|3x - 5| \ge 22\]Means,\[3x - 5 \ge 22\]or\[3x - 5 \le -22\]

Answer 6

\[x \ge 9\]or\[x \le \dfrac{-17}{3}\]

Answer 7

Well, now it may seem easier for you

Answer 8

Does it?

Answer 9

so the answer would be...

Answer 10

\[[9,\infty)\cup(-\infty,-17/3]\]

Answer 11

correct?