Question

Question on infinite series - using comparison test.

Answer 1

I've tried it multiple times but there has to be something that I'm missing, tried different answers but I'm fairly set on these ones, just not sure whats wrong

Answer 2

For (3) are you sure that \(\frac1{n^2-6}\lt\frac1{n^2}\)?

Answer 3

no now that i look at my notes \[\frac{ 1 }{ n^2-6 } > \frac{ 1 }{ n^2 }\]
good catch but im still messing up on one or more...

Answer 4

Careful about using the direct comparison test on series with negative terms... see #5, #6.

Answer 5

C,C,I,I,C,I

Answer 6

Thank you @oldrin.bataku

Answer 7

i over looked that the 5-n^3 acting like it was n^3-5 that was a bad mistake
thank you very much though

Answer 8

No problem, glad you figured it out. You'd need to show \(\left|\frac{n}{5-n^3}\right|<\frac1{n^2}\) you'd have been good, though.