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Mathematics
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OpenStudy (anonymous):
reduce the fraction to the lowest terms. someone please help me
13 years ago
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OpenStudy (anonymous):
yeah what can I help you with!
13 years ago
OpenStudy (anonymous):
\[\frac{ x ^{3}-{x ^{2}} }{ x ^{4} }\]
13 years ago
OpenStudy (anonymous):
will u help
13 years ago
OpenStudy (anonymous):
x^2((x-1)/(x^2))
13 years ago
OpenStudy (anonymous):
what
13 years ago
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OpenStudy (anonymous):
I don't understand this
13 years ago
OpenStudy (anonymous):
@Golferguy158 will u help me
13 years ago
OpenStudy (jim766):
What is the GCF of the numerator?
13 years ago
OpenStudy (anonymous):
7X
13 years ago
OpenStudy (anonymous):
You factor out an x^2 from the whole equation, and that will give you your answer.
13 years ago
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OpenStudy (anonymous):
does that make sense?
13 years ago
OpenStudy (anonymous):
no can u set it up for me so I can work it out
13 years ago
OpenStudy (jim766):
\[\frac{ x^3-x^2 }{ x^4 }=\frac{ x^2(x-1) }{ x^4 }\]
13 years ago
OpenStudy (anonymous):
I confused
13 years ago
OpenStudy (phi):
the first step is factor the top
\[ (x^3 - x^2) = (x\cdot x \cdot x - x \cdot x) \]
notice that both terms have x*x in them...
you can factor out x*x to get:
(x*x)*(x - 1)
now expand the bottom to x*x*x*x
cancel x*x
13 years ago
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OpenStudy (anonymous):
so it would look like
\[\frac{ x*x*(x-1) }{x*x }\]
13 years ago
OpenStudy (anonymous):
that's close, but the X^2 or in that case x*x on the top should be out in front of the equation.
13 years ago
OpenStudy (anonymous):
|dw:1366250368703:dw|
13 years ago
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