Question

Help... please...
simplify the radical expression. √(72x²)

Answer 1

\[6x \sqrt{2}\] ?

Answer 2

\[\sqrt{72x^2}= \sqrt{36} \sqrt{2}\sqrt{x^2}\]

Answer 3

do you see how @Jello_Submarine got that?

Answer 4

\[\sqrt{(72x ^{2})} = \sqrt{(2\times4\times9\times x ^{2}} = 2\times3\times x \times \sqrt{2} = 6x \sqrt{2}\] For clarification.

Answer 5

my computer is messing up. i cant really understant much of the equation you guys are posting. How did you get the answer?

Answer 6

You make 72x^2 into multipliers like 72x^2 = 2*4*9*x^2 and you notice, that you can bring out 4, 9 and x^2 from the square root and put them in front of the root, so you get 2*3*x*sqrt(2) as you can't bring out 2 from there.

Answer 7

you took 4 and 9 out. how did you get 3?

Answer 8

sq rt of 4 = 2
sq rt of 9 = 3

2 * 3 = 6

Answer 9

o i get it now! the equations finally showed up

Answer 10

\[\sqrt{72} = \sqrt{9}\sqrt{4}\sqrt{2}\]
\[\sqrt{72}= 3 * 2 \sqrt{2}\]
\[\sqrt{72}= 6 \sqrt{2}\]

Answer 11

thanks!