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Mathematics 15 Online
OpenStudy (anonymous):

Your group has decided to open a small business selling dry erase markers. An important thing to decide is what would be the best price to charge for the markers. After doing some market research, you found that if the markers cost $4 no one will buy them. However, if you charge nothing you'd end up giving away your whole inventory of 500 markers. The best price will be somewhere between these extremes. Graph this relationship and find the linear equation n=? that describes the situation

OpenStudy (anonymous):

@Mertsj

OpenStudy (mertsj):

Electroid will help you.

OpenStudy (anonymous):

ohkay :)

OpenStudy (mertsj):

The only thing I can think of based on the limited information is that is the price is 4 the number sold is 0 which gives the ordered pair (4,0) If the price is 0, the "number sold" is 500 which gives the ordered pair (0,500) so use p for x and n for y and write the equation of the line which contains those two points.

OpenStudy (anonymous):

Thank you so much! I have another question.

OpenStudy (mertsj):

ok

OpenStudy (anonymous):

The other question is: Use your graph to find the linear equation n= ? that describes the situation

OpenStudy (mertsj):

The linear equation is the equation of the line you just wrote using the two ordered pairs.

OpenStudy (mertsj):

Graph the ordered pairs, draw the line, write the equation of the line and you are done.

OpenStudy (anonymous):

sry peop[le had to leave.

OpenStudy (anonymous):

the number of markers is "y" and the cost is "x" when x=0, n=500 -> y-intercept when x=5, n=0 -> xintercept

OpenStudy (mertsj):

Do you mean when x = 4, n=0?

OpenStudy (anonymous):

oh yes.

OpenStudy (anonymous):

slope = (500-0)/(0-4)=-125

OpenStudy (anonymous):

\[n=-125x+500\]

OpenStudy (anonymous):

Oh I understand thank you. & what about this? If you sell n markers at a price p, your income will be their product n times p. Use the formula for your income in terms of p only

OpenStudy (anonymous):

\[i=n\times p\\ i=(-125p+500)\times p\]

OpenStudy (anonymous):

would -125p be squared?

OpenStudy (anonymous):

why do you think so?

OpenStudy (anonymous):

because when you multiply the equation by p p times p is p squared correct?

OpenStudy (anonymous):

yep.. just the "p" part.

OpenStudy (anonymous):

so,\[i=-125\times p^2+500p\]

OpenStudy (anonymous):

so would you rearrange the equation?

OpenStudy (anonymous):

na, I'd leave it like that. kinda lazy person I am

OpenStudy (anonymous):

oh ohkay aha thank you. I just have one more question when you graph the first equation (0,4) , (0,500) would it be a line seqgment or a line with arrows at the end?

OpenStudy (anonymous):

well, do you think "n" can go negative? or "p" can go negative?

OpenStudy (anonymous):

no because we're dealing with dollars, right?

OpenStudy (anonymous):

yeap and the number of markers neither can be negative.

OpenStudy (anonymous):

ohh ohkay so to be clear, it is not a line with arrows right?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

ohkay thank you soooo much!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

@Mertsj a medal is in order :)

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