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Mathematics 8 Online
OpenStudy (anonymous):

Dear, Math talent. Please help me with intergals

OpenStudy (anonymous):

\[\int\limits_{?}^{?}(xcos(x^3))^2dx\]

OpenStudy (anonymous):

heres ? in the question!

OpenStudy (anonymous):

multiply it out first, will turn your integral into one that can be solved with a substitution.

OpenStudy (anonymous):

there is a part missing. is it equal to something?

OpenStudy (anonymous):

@Dodo1 ?

OpenStudy (anonymous):

No not equal!

OpenStudy (anonymous):

@electrokid

OpenStudy (anonymous):

It seems that the question is incomplete!!!

OpenStudy (anonymous):

let me write it again

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

if you can post a picture of the problem that would be nice too

OpenStudy (anonymous):

\[\int\limits_{}^{}(xcos(x^3))^2)dx \]

OpenStudy (anonymous):

sorry I wont be able to post photos my phone is not working but this is the question which is written in the paper.

OpenStudy (anonymous):

in the original problem you have "?"symbols at the integration limits

OpenStudy (anonymous):

it also says compute te following intergrals

OpenStudy (anonymous):

Sorry theres no ?!

OpenStudy (anonymous):

∫(xcos(x^3))2)dx=∫1/3x^3(cos(x^3))^2)dx=∫1/3(cos(x^3))2)dx^3=∫1/3(cost)^2dt =∫1/3(cos2t/2+1/2)dt u should be able to do the rest

OpenStudy (anonymous):

thats what confused the people here... so\[ \int[x\cos(x^3)]^2dx=\int x^2\cos^2(x^3)dx \] solve by substitution \[u=x^3\implies du=3x^3dx\\ {du\over3}=x^2dx\] so, we get \[\int\cos^2(u){du\over3}={1\over3}\int\cos^2(u)du\] then we have the double angle rule: \[\cos^2\theta={\cos2\theta-1\over2}\]

OpenStudy (anonymous):

so, it reduces to \[{1\over3}\int\left(\cos(2u)-1\over2\right)du\\ \quad={1\over6}\int[\cos(2u)-1]du\\ \quad={1\over6}\left[????\right] \]

OpenStudy (anonymous):

you can solve from here :)

OpenStudy (anonymous):

once you get the integration, replace "u" back by the substituion in "x"

OpenStudy (anonymous):

cos2*x^3??

OpenStudy (anonymous):

du =1/3?/

OpenStudy (anonymous):

dont put in "x" yet.. lets solve the integral in terms of "u"

OpenStudy (anonymous):

u(cos2)-(1)?

OpenStudy (anonymous):

\[ {1\over6}\int\cos(2u)du-{1\over6}\int du \]

OpenStudy (anonymous):

I separated them

OpenStudy (anonymous):

what is the integral of cos(2u)?

OpenStudy (anonymous):

i am not 100 % the defition of integral...

OpenStudy (anonymous):

is it derivative?

OpenStudy (anonymous):

it is opposite of derivatives "derivative of what is cos(2u)?"

OpenStudy (anonymous):

cosu^2?

OpenStudy (anonymous):

check. do not guess take the derivative of what you just said and see if you get cos(2u)

OpenStudy (anonymous):

i am not guessing. i actually thought it was the answer.

OpenStudy (anonymous):

hmm whose derivative is cos(u)??

OpenStudy (anonymous):

2cosu?

OpenStudy (anonymous):

\[{d\over du}\sin(u)=?\]

OpenStudy (anonymous):

o... from the rule. cosx=sinx sinx=-cosx ?

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

those are the rules for integration

OpenStudy (anonymous):

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