2Mg(s) + O2 -- 2MgO How many moles of oxygen would be required to completely react with 46 grams of magnesium?

Question

2Mg(s) + O2 --> 2MgO  How many moles of oxygen would be required to completely react with 46 grams of magnesium?

anonymous · Answer

First find the number of Mg in mol. The number of oxygen required is one-half of the number of Mg. Need me to spell it out more?

abb0t · Answer

can you spell it out, please.

anonymous · Answer

The number of Mg (in mol) = (mass of Mg) / (formula weight of Mg)

The formula weight is just the mass of one mol of Mg atoms.

anonymous · Answer

so the number of Mg atoms is approx. 46 grams / 24.3 grams per mol

the number of O2 molecules is one-half of the number of Mg atoms.