Question

How many grams of iron metal do you expect to be produced when 325 grams of an 87.5 percent by mass iron (II) nitrate solution reacts with excess aluminum metal? Show all of the work needed to solve this problem.

2 Al (s) + 3 Fe(NO3)2 (aq) 3 Fe (s) + 2 Al(NO3)2 (aq)

Answer 1

what is molar mass of Fe(NO3)2

Answer 2

180

Answer 3

and atomic mass of Fe

Answer 4

55.845

Answer 5

180*3 gram of iron nitrate is used to produce the 55.845*3 g of Fe
Right

Answer 6

yeah

Answer 7

540 gram of iron nitrate is used to produce the 167.53 g of Fe
325 gram of iron nitrate is used to produces = 167.53*325 /540
= can u answer this

Answer 8

100.82 ?

Answer 9

this value is when 100 % of Fe nitrate we considered as to be reacted
but they say around 87.5 wt % only reacted
then 100 % - 100.82
87.5 % = 100.82 *87.5 /100 = find it

did you get it

Answer 10

88.21

Answer 11

yaaa hats the answer

Answer 12

thank you! @chmvijay

Answer 13

you are welcome dude Just enjoy the chemistry with LOVE:)

Answer 14

should i roung up to 88.3?

Answer 15

no u got 88.21 right u cant do to 88.3 u can do only 88.2 why do u want it to be 88.3

Answer 16

ok just wondering thanks!