Question

can someone walk me through this please?
use a limit and evaluate the integral by hand to prove that the following:

Answer 1

\[\int\limits_{1}^{\infty}x^{-1.5}dx=2\]

Answer 2

@LolWolf and @mathslover maybe since you've helped me before?

Answer 3

By hand...? I don't quite get what that means, but:
\[
\lim_{a\to \infty}\left(\int_1^ax^{-1.5}\;dx\right)=\lim_{a\to \infty}\left[-\frac{x^{-.5}}{.5}\right]_1^a
\]Try evaluating that.

Answer 4

I think it just means without using the calculator to solve

Answer 5

Sorry I'm lost