A 1,000 kilogram car travelling with the velocity of +20. m/s decelerates uniformly at -5.0 m/s^2 until it comes to rest. What is the total distance the car travels as it decelerates to rest?

Question

anonymous · Answer

why not try the formula: $$v^2=u^2+2as$$
where v=0 m/s
u=20m/s
a=-5m/s

and solve for s

anonymous · Answer

It says here the answer (the distance) is 40 meters. I just can't seem to put that into place. Anyway, I'll try to find the 's' just like what you've suggested. Thanks. :)

anonymous · Answer

Ignore the weight of the car as you do not need it to calculate the distance travelled.

anonymous · Answer

@SweetsAndEverything do you need me to explain further?

anonymous · Answer

if you don't mind. :)

anonymous · Answer

the equation is: v^2=u^2+2as
substitute the values in:|dw:1366362212274:dw|
v=final velocity (0 because you've stopped)
u=initial velocity (20 because that is the inital speed)
a=acceleration (-5 because your stopping)
s=distance travelled