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Chemistry 11 Online
OpenStudy (anonymous):

Calculate the pH of 0.020 moldm^-3 NaOH.....

OpenStudy (anonymous):

@chmvijay

OpenStudy (anonymous):

@Yahoo!:

OpenStudy (anonymous):

You are provided with the molarity (no. of moles per unit volume) of the NaOH, now calculate its pH using the formula \[pOH=-\log_{10} (Molarity of the base)\] then use the relation pH + pOH = 14 and use the value of the calculated pOH and find pH. pH = 14 - pOH

OpenStudy (anonymous):

ok...thank you! I get that method......

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