I need to ALGEBRA-FY a problem. This requires changing a mathematical word problem into a algebra word problem that has an equation such as arithmetic or recursive? So an example given to change a problem is: Traditional Arithmetic Problem Jack wants to save up to buy ______ that costs $35. He makes $5 per hour babysitting. How many hours will he need to work in order to buy the _____. Algebra-fied Arithmetic Problem Suppose the price of the ____ is on sale for $30, or Jack decides to purchase a more expensive one at $45. If you want to stress multiplying by 7, give Jack a raise to $7 per hour
Math and algebra are different??? No matter...state your problem so we can look at it.
So an example given to change a problem is: Traditional Arithmetic Problem Jack wants to save up to buy ______ that costs $35. He makes $5 per hour babysitting. How many hours will he need to work in order to buy the _____. Algebra-fied Arithmetic Problem Suppose the price of the ____ is on sale for $30, or Jack decides to purchase a more expensive one at $45. If you want to stress multiplying by 7, give Jack a raise to $7 per hour
Traditional Arithmetic Problem: Jack wants to save up to buy ______ that costs $35. He makes $5 per hour babysitting. How many hours will he need to work in order to buy the _____. Sounds like algebra to me. Let "x" be "how many hours do I have to babysit these brats" before I can buy my ___? The answer is: x=35/5 So it looks like Jack has 7 more brat-filled hours of joy to go... Algebra-fied Arithmetic Problem: Suppose the price of the ____ is on sale for $30, or Jack decides to purchase a more expensive one at $45. If you want to stress multiplying by 7, give Jack a raise to $7 per hour This isn't algebrecation, they're just variations on the last problem. If ___ remains on sale for 30$, Jack only has to babysit for 30/5 hours. If Jack wants the more expensive unit, he has to babysit for 45/5 hours. If Jack gets a raise to $7/hour, then the $35 unit will take 35/7 hours to get, if it goes and stays on sale at 30 it will take him 30/7 to get it, and if he wants the more expensive unit then he'll need to work 45/7 hours.
Yeah, agreed. You could easily create an algebraic expression for each of those.
okay thank you
No problem! Glad I could help!
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