A bag contains 5 red marbles, 6 white marbles and 5 blue marbles. Find P(red or blue)
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OpenStudy (anonymous):
p is 5
OpenStudy (anonymous):
thank you
OpenStudy (kropot72):
The events 'draw red' and 'draw blue' are mutually exclusive. Therefore the required probability is the sum of the individual probabilities.
\[P(red\ or\ blue)=\frac{5}{16}+\frac{5}{16}=you\ can\ calculate\]
OpenStudy (anonymous):
P(red or blue) = P(red) + P(blue) = 5/16 + 5/16
OpenStudy (anonymous):
Then to find the experimental probability if needed simplify the sum from \[\frac{ 10 }{ 16? }\] to get your experimental probability.
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OpenStudy (anonymous):
Forget that question mark it got in the way.
OpenStudy (anonymous):
Do you mean in decimal?
OpenStudy (anonymous):
In fraction
OpenStudy (anonymous):
Like the experimental probability of 8\[\frac{ 80 }{ 100 }\] is \[\frac{ 4 }{ 5 }\]
OpenStudy (anonymous):
Forget that 8 also after of
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
Was a mistake
OpenStudy (anonymous):
that means you need to simplify 10/16 = (2*5)/(2*8) = 5/8
OpenStudy (anonymous):
Just a sec
OpenStudy (anonymous):
Yes correct
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