Question

csc^2 45degree- tan^2 45degree

Answer 1

\[\csc ^{2}45degree= \left(\begin{matrix}\pi\\ 4\end{matrix}\right)=1\]
\[\tan ^{2}=\left(\begin{matrix}\pi \\ 4\end{matrix}\right)=1\]
I got zero and it doesnt look right for an answerr

Answer 2

well, check your unit circle, what's the CSC(45)?

Answer 3

\[\left(\begin{matrix} \pi \\4\end{matrix}\right)\]

Answer 4

pi/4

Answer 5

well, 45 degress expressed in radians is yes, pi/4, but that's not the value of it

Answer 6

http://i.stack.imgur.com/r8uHr.gif :)

Answer 7

\[\left[\begin{matrix}\sqrt{2} & 2 \\ \sqrt{2} & 2\end{matrix}\right]\]

Answer 8

from the graph, those the (cos,sin) values, yes :)

Answer 9

squr. root of 2 over 2 n sqru over 2. i subract both and i got zero

Answer 10

well, you want ... CSC, no sine or cosine, check your trigonometry formulas cheatsheet for the "reciprocal identities", what is CSC equals to?

Answer 11

\[\frac{ 1 }{ x}\]csc=

Answer 12

http://www.sosmath.com/trig/Trig5/trig5/img1.gif

Answer 13

i still lost

Answer 14

1

Answer 15

well, from the sheet on that graphic, you can see that \[csc(\theta)=\frac{1}{sin(\theta)}\] thus \[csc(45)=\frac{1}{sin(45)}\]

Answer 16

\[sin(45)=\frac{\sqrt{2}}{2} \ and\ thus \frac{1}{\frac{\sqrt{2}}{2}}= \frac{2}{\sqrt{2}}=csc(45)\]