(f^-1) of f(x) = ( x^(3)+2) at (1 , 3).
Inverse of function?
Yes, please
the 'at (1, 3)' is throwing me off
i think its irrelevant? so just find inverse
I think its just a saying that you should let y=f(x), you see, \[f(x)=x^3+2, \] when y=f(x), \[y=x^3+2\] 3=1+2 3=3
why would it say \(f^{-1}\)? i think its asking for inverse
Inverse goes with \[y=f(x) \\ \\ y=x^3+2 \\ \\ ^3\sqrt{y-2}=x \\ \\ f^{-1}(x)=^3\sqrt{x-2}\]
Yup, inverse
yeah correct btw proper way to write cube root is \sqrt[3]{x} \[\sqrt[3]{x}\]
I'm liking Sam's Answer.
yes with the \(\pm\)
no you dont need +- because its cube its odd number
\text{} doesn't work btw
im not using \text{}?
if you don't believe me that you don't need +- here's a solution generated by computer http://www.wolframalpha.com/input/?i=inverse+of+f%28x%29+%3D+x%5E3%2B2
I do guys, thanks a lot. I already love this site
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