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OpenStudy (gorv):

Six letters are picked. Find the chance that they can be arranged to form the word RANDOM.

OpenStudy (campbell_st):

well you pick 6 from 26 and assuming there is no replacement 5 from 25 4 from 24 3 from 23 2 from 22 and 1 from 21 multiply the probabilities to get the chance of selecting the word RANDOM

OpenStudy (anonymous):

hmmm im going to use formula probability = favorable events / total number of ways there is 1 way to pick the six letters RANDOM in that order. there is 26x25x24x23x22x21 ways to pick any 6 letters in order.

OpenStudy (anonymous):

1 / ( 26 P 6 )

OpenStudy (campbell_st):

@wilson3 if you read the question, order isn't important

OpenStudy (anonymous):

yes order is important. it says the word "RANDOM" , which is not the word DOMRAN

OpenStudy (anonymous):

im thinking that he picked 6 letters from the set of alphabet, and does not replace it

OpenStudy (anonymous):

Picking letters doesn't use up the alphabet. All the letters are always there. Order isn't important because gorv wants the odds that they "CAN BE ARRANGED" to form a word.

OpenStudy (anonymous):

lol, ok. if picking letters doesnt use up alphabet the chance is 1 / 26^6

OpenStudy (anonymous):

well this question is bloody ambiguous

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