Question

prove that

Answer 1

Let \(\sin^{-1}6x=\alpha\). then \(\sin\alpha=6x\)
Let \(\sin^{-1}(6\sqrt3x)=\beta\). then \(\sin\beta=6\sqrt3x\)
\(\sin(\alpha+\beta)=\sin\alpha\cos\beta+\sin\beta\cos\alpha\)
\(\cos\alpha=\sqrt{1-\sin^2\alpha}\)
\(\cos\beta=\sqrt{1-\sin^2\beta}\)
u need to show
\(\sin^{-1}(\alpha+\beta)=-\pi/2\)
Does that help?

Answer 2

u mean this?
\(\Large\sqrt[6]{3x}\)

Answer 3

is it a word problem?