How do you find the height of the arch?? A bridge is built in the shape of a semiplliptical arch. The bridge has a span of 80 feet and a mas height of 20 feet. Choose a suitable rectangular coordinate system and find the height of the arch at a distance of 30 feet from the center. The height is about ______ feet (round to two decimal places)
draw it out
you want x=0, y=20 y=0, x=80/2 then what is the value of that when x=20?
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what do you mean x=20?
@amistre64
i meant x=30, just hit the wrong key on the keyboard.
\[\frac{x^2}{p^2}+\frac{y^2}{q^2}=1\] \[\frac{y^2}{q^2}=1-\frac{x^2}{p^2}\] \[y^2=q^2-\frac{(qx)^2}{p^2}\]
q=20, p=40, and x=30 if i se it right
so you are trying ot find for y? since 30 is x
yes
so what am I suppose to do with y? wait thats the height?
lol, yes. that will be the height at any value of x
y^2 = some # y = sqrt(some #)
when x=p, we have q^2 = q^2 = 0 which is what we would expect at a distance of p from the center.
so would it be 18.97 for the height of the arch
maybe, let me check my calculator ....
i get something closer to 13
\[y=\sqrt{20^2-\frac{(20*30)^2}{40^2}}\]
okay thank you for the correcting me!
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