how to find the absolute value of a function
if the function is \[\frac{ n(x-1) }{ -5(n+1) }\]
then would the absolute value be \[\frac{ n \left| x \right|-n }{ 5(n+1) }\]
or would I need to change the -n to +n?
this is for a series by the way, so the n's are always positive
Remember the law of absolute values for a variable 'x'. Think of it as a peacewise defined function whereby it states the following: \[x =x\ if x \ge0\] and \[x =-x if x < 0\] so where x is make sure that you have both cases (IE. You will have two equations to work with). One question will be with x = x assuming x >= 0. Or -x assuming x < 0.
okay thanks :)
they are obviously asking you to provide both of the two types of equations you will be working with. I cant imagine them just asking you to put the absolute value signs by the x and that will give you marks. so solve for the two parts of the equation - 1.) where x = x and 2.) where x = -x
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