Question

the ionic equation for MgCl2 and KOH

Answer 1

there are two types of ionic equation: complete or net. which type are you thinking of?

Answer 2

both

Answer 3

i guess we are mixing MgCl2 with KOH, both solutions of soluble salts. the balanced equation looks like:

MgCl2(aq) + 2KOH(aq) -> Mg(OH)2(s) + 2KCl(aq)

MgCl2, KOH and KCl are soluble (hence "aq"), but Mg(OH)2 is insoluble, hence "s".

the soluble salts dissociate into ion (pairs) in solutions, so the equation looks like:

Mg^2+ + 2Cl- + 2K+ + 2OH- -> Mg(OH)2(s) + 2K+ + 2 Cl-

See how potassium and chloride appear on both sides. this means we can cancel them out and we end up with:

Mg^2+(aq) + 2OH-(aq) -> Mg(OH)2(s)

Answer 4

complete:
Mg^2+ + 2Cl- + 2K+ + 2OH- -> Mg(OH)2(s) + 2K+ + 2 Cl-

net:
Mg^2+(aq) + 2OH-(aq) -> Mg(OH)2(s)

ions are in aqueous phase, so the complete equation i wrote is missing the "aq"s here and there.

in any case, don't take my word for it. verify things for yourself too.

Answer 5

Okay thank you for your help!