Where does the graph of y = 6x2 − 11x − 10 cross the x-axis Answers must be fractions? Dont get it
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At the point, where the graph crosses the x-axis, the value of the y-coordinate is 0.. therefore to find the value of x at that point (where curve crosses the x-axis), your equation now becomes \[0 = 6x ^{2}-11x-10\]
I know i just dont know how to get answers in fraction form
well the easiest way is to use the general quadratic formula \[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\] in your question a =6, b = -11 and c = -10 substitute them and evaluate
Factor it: (3x+2)(2x-5)=0 You gonna get fractiolns when you solve it.
i did..... i need answers in fraction form as I stated multiple times
if 3x+2 = 0, you will get a fraction if you solve for x... same with the other factor that radar gave you
use the quadratic formula above, or if it factorizes easily then factor it out. Solve for x. You should get two "fractions".
How did you get that @radar
If you solving for the X intercept. It means Y is going to be 0. So set y to 0. Then you get =0. Solve for x using two methods: Factorizing like radar did, or plugging the values from the quadratic into the QUADRATIC FORMULA to get your two x values.
@adziz there really is no need for your smartassery
I did it by looking at 6 breaking it down to factors 3 and 2, then doing some minor trial and error by multiply ing each of those by the factors of 10 which are 5 and 2 and noting the signs, come up with a product that when summed equals -11. Takes practice but it becomes pretty reasonable.
ok
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