Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Which rules should I use to find this derivative?

OpenStudy (anonymous):

If I want to find the derivative of: \[f(x)=\frac{ (3x ^{2}+1)(2x-1) }{ (5x+4) }\] Which rules would I use and in which order?

OpenStudy (anonymous):

I know I could just foil out the top, but would it make sense do to the Product Rule as well as the Quotient Rule? If so, which order should I use them in?

OpenStudy (anonymous):

to simplify, i'd suggest you foil it then do the quotient rule

OpenStudy (anonymous):

What would I do if it were too obnoxious to do the foil rule? For example: \[f(x)=\frac{ (3x-4)^{9} }{ 5x-2 }\]

OpenStudy (anonymous):

with that you can just use the quotient rule since there is (3x-4)^9 instead of something like (3x-2)^8*(2x-3)^7, that would require both product and quotient rule

OpenStudy (anonymous):

I guess what I'm asking is how do I go about finding a derivative when I'm required to use both the quotient and product rule.

OpenStudy (anonymous):

(Because I guess actually that last example would require the chain rule, not the product rule.)

zepdrix (zepdrix):

\[f(x)=\frac{ \color{orangered}{(3x ^{2}+1)(2x-1)} }{ (5x+4) }\] In your first example, you have the product rule `within` the quotient rule. So you would apply the quotient rule first, and then whenever you're asked to differentiate this orange part, you apply the product rule.

zepdrix (zepdrix):

And yes, beyond that, you would need to apply the chain rule after applying the product rule :)

OpenStudy (anonymous):

^

OpenStudy (anonymous):

Thank you so much! :)

zepdrix (zepdrix):

np. If you need to see that one worked out, lemme know c:

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!