Question

An urn contains 10 white balls and 5 blue balls. Draws are made repeatedly from the urn as follows. On each draw, a ball is drawn and its color noted; then it is replaced in the urn along with 3 more balls of its color. help . Find the chance that the second ball drawn is blue = 5/15*8/18 . is correct ?

Answer 1

Find the chance that the first ball drawn is blue =1/3

Answer 2

It's just \[\frac{ 8 }{ 18}\] for the chance of blue being drawn the 2nd time when 3 more blue balls were added. You are not finding the chance that a blue ball is drawn two times in a row, just the 2nd time.

Answer 3

or 7/17 ?

Answer 4

It's 18 I think, 15+3 = 18

Answer 5

the denominator

Answer 6

mm ok ..thk

Answer 7

now is question Find the chance that the first ball drawn is blue, given that the second ball drawn is blue ? P(B1/B2)

Answer 8

my aswer is P(B1/B2)=4/9 is correct ? .. look my diagram

Answer 9

P(B1 and B2) =? hello ?

Answer 10

is 4/27 ?

Answer 11

P(B1/B2) is 4/9