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find the absolute maximum and minimum f(x)=x^2+4x; on [-5,5]
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Did you find the vertex of this parabola?
no.. I thought you just had to find the derivative and then plug in for x...
I guess it depends on what chapter you are studying.
haha can you help? :)
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The x coordinate of the vertex is -b/2a. It is in the given interval?
yeah check out my screen shot of the problem
So, to find the minimum, plug the x coordinate of the vertex into the equation and find the y coordinate. That will be the absolute minimum of the parabola and thus the absolute minimum in the prescribed interval.
yeah i got 16 for the max and -6 for the min but it says its wrong....
|dw:1366504533410:dw|
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