Question

A trapezium ABCD with AD//BC. 13 years ago

Answer 1

@jayz657 would you kindly help me?

Answer 2

so part a should look something like this

Answer 3

yup, i am the same with you

Answer 4

so use the pythagorean theorem to find the base

Answer 5

sorry use cos(68) = x/8.4

Answer 6

3.1467?

Answer 7

yea so since its a parallelogram then the other half of the base should have the same length

Answer 8

wait, x is what?

Answer 9

so pc = 2(3.1467) =6.293

Answer 10

but the answer is 5.38

Answer 11

ohh, i got the answer 5.58 now, but how about part c?

Answer 12

well im not exactly sure about part b but it should be along those steps to find part c you can use the [1/2(answer from part b) + 9.2] x height

height = sqrt(((answer from part b)^2 + 8.4^2))

Answer 13

74.5?

Answer 14

hm.. i got around 121

Answer 15

wait let me try again

Answer 16

the answer is 92.6

Answer 17

@satellite73 genius, would you kindly help me :)

Answer 18

sorry im sure someone more experienced can help you

Answer 19

but i think @satellite73 is busy..

Answer 20

i be afk for half an hour, got something to do, and i help you if someone hasnt yet

Answer 21

I figured it out if you still need help

Answer 22

what's your idea?

Answer 23

i got the answer the answer key got, sorry i was distracted while helping you before so yea..
but i got it now give me like 10 mins to type out everything

Answer 24

so looking at the diagram to find the base you do
cos(68) = x/8.4
so you should get x = 3.147

now to find the other part of the base you need to find height first so
a^2 + b^2 = c^2
3.147^2 + b^2 = 8.4^2
b = 7.78822

now you do tan(74) = 7.78822/y
y = 2.332
so PC = 2.332 + 3.147 = 5.479 <- i rounded so it should be 5.58

now to find area you need to find the bottom base
which is 3.147 + 9.2 + 2.233 = 14.58

then use area of trapezoid: A = 1/2(b1+b2)(h)
A = (14.58+9.2)(7.78822) / 2 = 92.6019358