Question

Consider a triangle ABC with interior angles A, B and C, and the corresponding opposite sides a,b and c. Show that the area of ABC is given by : [a^(2)sinBsinC]/(2sinA)
[URGENT]

Answer 1

OK. So trig ratios.

Answer 2

Now, we know it is a triangle, but not if it is right or not. So we have to use something other than the typical 1/2 bh.

Answer 3

yeah

Answer 4

We have to arrive at:\[\frac{a^{2}\sin B\sin C}{2\sin A)\]

Answer 5

yup...

Answer 6

Hmm... the math formatting did not work right for me there. Odd.
AH! I see the mistake.
\[\frac{a^{2}\sin B\sin C}{2\sin A}\]
OK. There we are. If you think about it, there are right triangles hidden in there that tell you a bit about the relationships between the different angles.

Answer 7

what do you mean?