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Mathematics 14 Online
OpenStudy (anonymous):

Find the area under the normal distribution curve between z = 1.52 and z = 2.43

jimthompson5910 (jim_thompson5910):

You can use a TI-83/84/89 etc or you can use wolfram alpha http://www.wolframalpha.com/input/?i=normalcdf%281.52%2C2.43%29 to get P(1.52 < Z < 2.43) = 0.05671

OpenStudy (anonymous):

thank you!

jimthompson5910 (jim_thompson5910):

yw

OpenStudy (anonymous):

ugh I hate math! This is my hardest class ever

jimthompson5910 (jim_thompson5910):

just take things one step at a time and know that there are tons of tools out there to help

jimthompson5910 (jim_thompson5910):

like this calculator for instance

OpenStudy (anonymous):

Punching in a simple command in your calculator to determine the area sounds a heck of a lot easier than manually evaluating a Gaussian integral, so don't take that for granted...

jimthompson5910 (jim_thompson5910):

well you need calculus for that oldrin.bataku...which I'm assuming HelloAshley hasn't learned yet

OpenStudy (anonymous):

That's my point! :-p this class while it may seem challenging is a lot easier now than it might've been 60 years ago.

OpenStudy (anonymous):

I haven't taken a full class of calculus. I'm in my survey of mathematical methods. I'm basically learning all types of math. It jumps around a lot

jimthompson5910 (jim_thompson5910):

sounds like an interesting class, never had anything like it

OpenStudy (anonymous):

it's really hard. I'm terrible at math and it's a super fast paced class and we don't get to spend enough time on each type of math so it is very demanding

OpenStudy (anonymous):

@HelloAshley well if you ever need anything you can always ask for explanations here!

jimthompson5910 (jim_thompson5910):

is it one of those courses where it's all crammed into 5-7 weeks?

OpenStudy (anonymous):

I wish I would have known of this much sooner. I only have one assignment left until I am done with the class. Thank God! Yes it is all crammed into 5 weeks.

jimthompson5910 (jim_thompson5910):

thought so, I hate those course schedules...way too much info to squeeze into a very tight window not much learning gets done when you're blazing through it that quickly

OpenStudy (anonymous):

I agree! Stupid thing is that I won't use any of the math I am learning

jimthompson5910 (jim_thompson5910):

yes you will (ok you might), so you never know

jimthompson5910 (jim_thompson5910):

always good to keep your mind open because that's how you improve your odds of landing the job you want

OpenStudy (anonymous):

I'm going to be a preschool teacher.

jimthompson5910 (jim_thompson5910):

i see, well it still won't hurt to know some of this stuff because you'll still need to do things like banking, borrowing money, etc

OpenStudy (anonymous):

Find the value for the correlation coefficient r; X= 5 1 4 2 3 Y= 5 10 12 4 8. is it –0.073 –0.094 –0.203 –0.149

OpenStudy (anonymous):

i got -0.094 but idk

jimthompson5910 (jim_thompson5910):

do you have a program like excel?

OpenStudy (anonymous):

You don't even have to use Excel... just compute the standard deviations and means. Least-squared models have coefficients that are readily computable esp. for small data sets.

OpenStudy (anonymous):

squares**

OpenStudy (anonymous):

no I don't have excel

jimthompson5910 (jim_thompson5910):

ok how did you get -0.094 ?

jimthompson5910 (jim_thompson5910):

was it just a guess or did you figure it out through some method or formula?

OpenStudy (anonymous):

TI-83 calculator

jimthompson5910 (jim_thompson5910):

ok hopefully you entered the two data sets into two lists then you used the 2-var statistics (under the stats/calc menu) option to find the answer it is -0.094 , so you are 100% correct

OpenStudy (anonymous):

yay! :D thanks. I think some times I just think I'm an idiot so I just need someone to tell me I'm either right or wrong, self esteem issue I think. I'm always second guessing myself

jimthompson5910 (jim_thompson5910):

well you should usually go with your instinct since it's usually correct second guessing leads to wrong answers a lot of the time I've noticed

OpenStudy (anonymous):

me too

OpenStudy (anonymous):

Which of the following is not a property of a normal distribution? It never touches the x-axis. It is continuous. The mean, median, and mode are equal. It is bimodal (i.e., it has two modes). I say it's this

jimthompson5910 (jim_thompson5910):

yep, it's symmetric about one peak and it doesn't have more than one peak so it's not bimodal (and it's unimodal)

OpenStudy (anonymous):

A data set of size 19 has correlation coefficient of r = –0.432. Test the significance of r at the 5% level and at the 1% level. I think its r is significant at 5% and at 1%. My choices are r is significant at 5% and at 1%. r is significant at 5%, but not at 1%. r is is not significant at 5% or at 1%.

jimthompson5910 (jim_thompson5910):

have you learned about hypothesis testing?

OpenStudy (anonymous):

yes

jimthompson5910 (jim_thompson5910):

ok so what makes you think it's significant at 5% and 1% ?

OpenStudy (anonymous):

i think its not significant at either....idk I'm confused

jimthompson5910 (jim_thompson5910):

let me see if I can find a page that explains the hypothesis test we'll use, one sec

jimthompson5910 (jim_thompson5910):

ok this page may help http://rmower.com/statistics/prog_calc_stat/How_to/Hypothesis_Test_Linear_correlation_TI-83-84_Plus_TI-Inspire%20w-84_keyboard.htm we'll be using the formula \[\large t = r\sqrt{\frac{n-2}{1-r^2}}\] in this case, r = -0.432 and n = 19, so... \[\large t = r\sqrt{\frac{n-2}{1-r^2}}\] \[\large t = -0.432\sqrt{\frac{19-2}{1-(-0.432)^2}}\] \[\large t = -1.974979\]

jimthompson5910 (jim_thompson5910):

The test statistic is \[\large t = -1.974979\]

OpenStudy (anonymous):

thanks

jimthompson5910 (jim_thompson5910):

did you manage to get this far? we're not done since we still need the critical values

OpenStudy (anonymous):

i get lost at this point. but i could have swore i was right with it not being significant at either

jimthompson5910 (jim_thompson5910):

oh you said not significant for both? i need my eyes checked lol yeah you're right about both, neither are significant

jimthompson5910 (jim_thompson5910):

the basic idea is to find the critical values for the 1% level and the 5% level then you see if the test statistic lies in the rejection region. If it does, then the value of r is statistically significant. If not, then it's not significant.

OpenStudy (anonymous):

phew lol i was starting to sweat on that one. lol. I thought it was one way and then i realized i was wrong & had a hard time going back to double check and got myself all confused.

jimthompson5910 (jim_thompson5910):

sadly it's kinda hard to explain, but I think that page may have an example maybe not...just looked back at it and it just has the formulas and such hmm maybe your lesson, videos, or notes has a better explanation

OpenStudy (anonymous):

my video wasn't much help. I'm trying to do a pre test as a warm up to my actual final test for the class and I am sucking :( I don't get graded on my pre test but I still don't want to do bad

jimthompson5910 (jim_thompson5910):

that's unfortunate, how about the notes then?

OpenStudy (anonymous):

I hate the wording in this, it always gets me confused when they try to trick you...Which statement is true for a statistical study? The sample is a subset of the population. The population is a subset of the sample.

jimthompson5910 (jim_thompson5910):

If A is a subset of B, then A is a smaller set (usually) that fits completely within the larger set B

OpenStudy (anonymous):

i dont have notes. its just a video and example in the book. thats about it. not helpful for sure, i wish they explained more

jimthompson5910 (jim_thompson5910):

example: A = set of all mammals B = set of all animals every mammal is an animal, so the set of mammals is completely in the set of animals so A is a subset of B

jimthompson5910 (jim_thompson5910):

the opposite is not true since you could easily have an animal that's not a mammal (eg: snake) so B is not a subset of A

OpenStudy (anonymous):

so the 1st answer then?

OpenStudy (anonymous):

idk y i find this so confusing

jimthompson5910 (jim_thompson5910):

correct, the sample fits in the population but the population doesn't fit in the sample

jimthompson5910 (jim_thompson5910):

here's a venn diagram |dw:1366526051758:dw|

OpenStudy (anonymous):

thats what i thought. i can do hard math is seems easier than i can do the stuff that is supposed to be easy. i over think

jimthompson5910 (jim_thompson5910):

yeah like i said, just take things one step at a time and don't panic

OpenStudy (anonymous):

Find the area under the normal distribution curve between z = –1.34 and z = 2.95? 0.908 i think its this 0.088 0.410 0.498

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

you got it

OpenStudy (anonymous):

Find the area under the normal distribution curve to the right of z = –1.03 0.151 –0.349 0.349 i think this one 0.849

jimthompson5910 (jim_thompson5910):

http://www.wolframalpha.com/input/?i=normalcdf%28-1.03%2C5%29

jimthompson5910 (jim_thompson5910):

what you want is the last row in the "probabilities" section

OpenStudy (anonymous):

so its 0.849

OpenStudy (anonymous):

i was way off then

jimthompson5910 (jim_thompson5910):

yes 0.849

OpenStudy (anonymous):

the 2nd time i did it i got .85 blah i drive myself nuts lol

jimthompson5910 (jim_thompson5910):

lol how are you getting these answers? are you using the calc I'm using?

OpenStudy (anonymous):

no i was using some other crap i just closed. it was too confusing. lol

jimthompson5910 (jim_thompson5910):

oh which is that if I may ask?

OpenStudy (anonymous):

For the 20 test scores shown, find the percentile rank for a score of 86. 75 63 92 74 86 50 77 82 98 65 71 89 75 66 87 59 70 83 91 73 I think its at the 70th percentile

jimthompson5910 (jim_thompson5910):

that given data set sorts to 50, 59, 63, 65, 66, 70, 71, 73, 74, 75, 75, 77, 82, 83, 86, 87, 89, 91, 92, 98

jimthompson5910 (jim_thompson5910):

86 is in slot #15 (out of 20 total slots) so it's in the (15/20)*100 = 75th percentile

jimthompson5910 (jim_thompson5910):

oh wait...then again there are actually 14 values below slot 15 so that would place it in the (14/20)*100 = 70th percentile so it sounds like you're correct

jimthompson5910 (jim_thompson5910):

nvm that last thought before where i got 75

OpenStudy (anonymous):

Count all the ones that are lower than 86. Number_of_lower_scores=14 Total_number_of_scores=20 i thought it'd be 14/20 which is 0.7 and then it's be 70%

OpenStudy (anonymous):

so 75 is right, right?

OpenStudy (anonymous):

i meant 70

jimthompson5910 (jim_thompson5910):

i think your initial answer of 70 is more correct

jimthompson5910 (jim_thompson5910):

now that I think about it

jimthompson5910 (jim_thompson5910):

yeah wasn't thinking with the 75 lol

OpenStudy (anonymous):

:)

OpenStudy (anonymous):

If a student's percentile rank in a class of 400 students is 87, find the student's class rank

OpenStudy (anonymous):

i say 52

jimthompson5910 (jim_thompson5910):

same data set?

jimthompson5910 (jim_thompson5910):

oh wait nvm

OpenStudy (anonymous):

choices 40 44 48 52

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