Find the area under the normal distribution curve between z = 1.52 and z = 2.43
You can use a TI-83/84/89 etc or you can use wolfram alpha http://www.wolframalpha.com/input/?i=normalcdf%281.52%2C2.43%29 to get P(1.52 < Z < 2.43) = 0.05671
thank you!
yw
ugh I hate math! This is my hardest class ever
just take things one step at a time and know that there are tons of tools out there to help
like this calculator for instance
Punching in a simple command in your calculator to determine the area sounds a heck of a lot easier than manually evaluating a Gaussian integral, so don't take that for granted...
well you need calculus for that oldrin.bataku...which I'm assuming HelloAshley hasn't learned yet
That's my point! :-p this class while it may seem challenging is a lot easier now than it might've been 60 years ago.
I haven't taken a full class of calculus. I'm in my survey of mathematical methods. I'm basically learning all types of math. It jumps around a lot
sounds like an interesting class, never had anything like it
it's really hard. I'm terrible at math and it's a super fast paced class and we don't get to spend enough time on each type of math so it is very demanding
@HelloAshley well if you ever need anything you can always ask for explanations here!
is it one of those courses where it's all crammed into 5-7 weeks?
I wish I would have known of this much sooner. I only have one assignment left until I am done with the class. Thank God! Yes it is all crammed into 5 weeks.
thought so, I hate those course schedules...way too much info to squeeze into a very tight window not much learning gets done when you're blazing through it that quickly
I agree! Stupid thing is that I won't use any of the math I am learning
yes you will (ok you might), so you never know
always good to keep your mind open because that's how you improve your odds of landing the job you want
I'm going to be a preschool teacher.
i see, well it still won't hurt to know some of this stuff because you'll still need to do things like banking, borrowing money, etc
Find the value for the correlation coefficient r; X= 5 1 4 2 3 Y= 5 10 12 4 8. is it –0.073 –0.094 –0.203 –0.149
i got -0.094 but idk
do you have a program like excel?
You don't even have to use Excel... just compute the standard deviations and means. Least-squared models have coefficients that are readily computable esp. for small data sets.
squares**
no I don't have excel
ok how did you get -0.094 ?
was it just a guess or did you figure it out through some method or formula?
TI-83 calculator
ok hopefully you entered the two data sets into two lists then you used the 2-var statistics (under the stats/calc menu) option to find the answer it is -0.094 , so you are 100% correct
yay! :D thanks. I think some times I just think I'm an idiot so I just need someone to tell me I'm either right or wrong, self esteem issue I think. I'm always second guessing myself
well you should usually go with your instinct since it's usually correct second guessing leads to wrong answers a lot of the time I've noticed
me too
Which of the following is not a property of a normal distribution? It never touches the x-axis. It is continuous. The mean, median, and mode are equal. It is bimodal (i.e., it has two modes). I say it's this
yep, it's symmetric about one peak and it doesn't have more than one peak so it's not bimodal (and it's unimodal)
A data set of size 19 has correlation coefficient of r = –0.432. Test the significance of r at the 5% level and at the 1% level. I think its r is significant at 5% and at 1%. My choices are r is significant at 5% and at 1%. r is significant at 5%, but not at 1%. r is is not significant at 5% or at 1%.
have you learned about hypothesis testing?
yes
ok so what makes you think it's significant at 5% and 1% ?
i think its not significant at either....idk I'm confused
let me see if I can find a page that explains the hypothesis test we'll use, one sec
ok this page may help http://rmower.com/statistics/prog_calc_stat/How_to/Hypothesis_Test_Linear_correlation_TI-83-84_Plus_TI-Inspire%20w-84_keyboard.htm we'll be using the formula \[\large t = r\sqrt{\frac{n-2}{1-r^2}}\] in this case, r = -0.432 and n = 19, so... \[\large t = r\sqrt{\frac{n-2}{1-r^2}}\] \[\large t = -0.432\sqrt{\frac{19-2}{1-(-0.432)^2}}\] \[\large t = -1.974979\]
The test statistic is \[\large t = -1.974979\]
thanks
did you manage to get this far? we're not done since we still need the critical values
i get lost at this point. but i could have swore i was right with it not being significant at either
oh you said not significant for both? i need my eyes checked lol yeah you're right about both, neither are significant
the basic idea is to find the critical values for the 1% level and the 5% level then you see if the test statistic lies in the rejection region. If it does, then the value of r is statistically significant. If not, then it's not significant.
phew lol i was starting to sweat on that one. lol. I thought it was one way and then i realized i was wrong & had a hard time going back to double check and got myself all confused.
sadly it's kinda hard to explain, but I think that page may have an example maybe not...just looked back at it and it just has the formulas and such hmm maybe your lesson, videos, or notes has a better explanation
my video wasn't much help. I'm trying to do a pre test as a warm up to my actual final test for the class and I am sucking :( I don't get graded on my pre test but I still don't want to do bad
that's unfortunate, how about the notes then?
I hate the wording in this, it always gets me confused when they try to trick you...Which statement is true for a statistical study? The sample is a subset of the population. The population is a subset of the sample.
If A is a subset of B, then A is a smaller set (usually) that fits completely within the larger set B
i dont have notes. its just a video and example in the book. thats about it. not helpful for sure, i wish they explained more
example: A = set of all mammals B = set of all animals every mammal is an animal, so the set of mammals is completely in the set of animals so A is a subset of B
the opposite is not true since you could easily have an animal that's not a mammal (eg: snake) so B is not a subset of A
so the 1st answer then?
idk y i find this so confusing
correct, the sample fits in the population but the population doesn't fit in the sample
here's a venn diagram |dw:1366526051758:dw|
thats what i thought. i can do hard math is seems easier than i can do the stuff that is supposed to be easy. i over think
yeah like i said, just take things one step at a time and don't panic
Find the area under the normal distribution curve between z = –1.34 and z = 2.95? 0.908 i think its this 0.088 0.410 0.498
good
you got it
Find the area under the normal distribution curve to the right of z = –1.03 0.151 –0.349 0.349 i think this one 0.849
what you want is the last row in the "probabilities" section
so its 0.849
i was way off then
yes 0.849
the 2nd time i did it i got .85 blah i drive myself nuts lol
lol how are you getting these answers? are you using the calc I'm using?
no i was using some other crap i just closed. it was too confusing. lol
oh which is that if I may ask?
For the 20 test scores shown, find the percentile rank for a score of 86. 75 63 92 74 86 50 77 82 98 65 71 89 75 66 87 59 70 83 91 73 I think its at the 70th percentile
that given data set sorts to 50, 59, 63, 65, 66, 70, 71, 73, 74, 75, 75, 77, 82, 83, 86, 87, 89, 91, 92, 98
86 is in slot #15 (out of 20 total slots) so it's in the (15/20)*100 = 75th percentile
oh wait...then again there are actually 14 values below slot 15 so that would place it in the (14/20)*100 = 70th percentile so it sounds like you're correct
nvm that last thought before where i got 75
Count all the ones that are lower than 86. Number_of_lower_scores=14 Total_number_of_scores=20 i thought it'd be 14/20 which is 0.7 and then it's be 70%
so 75 is right, right?
i meant 70
i think your initial answer of 70 is more correct
now that I think about it
yeah wasn't thinking with the 75 lol
:)
If a student's percentile rank in a class of 400 students is 87, find the student's class rank
i say 52
same data set?
oh wait nvm
choices 40 44 48 52
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