Question

Capacitors (related to derivatives)

Answer 1

With all capacitancies are in microfarads.
A 12 V battery is connected between points a and b in the circuit shown in the original circuit of the previous example.
Calculate the charge and voltage on the 4.0 μF capacitor.
Repeat the calculations for the 6.0 μF and 8.0 μF capacitors.

Answer 2

the second circuit is actually the simplified form of first circuit. when you have two capacitors connected in parallel,then thier equivalent capacitance is given by the sum of the individual capacitance.

Answer 3

do you know the formula for capacitance in terms of charge and voltage?

Answer 4

the potential difference across both the 2 mF and 4 mF capacitors is 12V since they are connected in parallel with the battery.

Answer 5

therefore charge on 2mF capacitor=Q=CV=2*12=24 coulomb

Answer 6

wait, wtf!!! there's no 8mF capacitor in the diagram you provided!!

Answer 7

ohh sorry

Answer 8

and i don't think you'll need derivatives to solve this question

Answer 9

derivatives are not required, just in my case we use derivatives to derive formulas, it is also possible to solve by staddard formulas

Answer 10

the only reason is that we use formulas that is not in the formula table

Answer 11

so i guess, you first derive the formula of capacitance for a parallel plate capacitor using derivatives,right??

Answer 12

no, use standard formulas

Answer 13

anyway thx