Question

general value of x which satisfy the equation 2sinx+1=0 ?

Answer 1

sin x= 1/2

Answer 2

You subtract one and then div by 2. So it should be sin x= -1/2

Answer 3

so what would be general value

Answer 4

\[\frac{ 7\pi }{ 6 } \pm 2\pi n\]

Answer 5

\[\frac{ 11\pi }{ 6 } \pm 2\pi n\]

Answer 6

Those would be your general solutions

Answer 7

in this n is natural number
but i don't have these in any of its options

Answer 8

What are your options?

Answer 9

Yes, n would be the natural number

Answer 10

options are
a)n(pi)- (-1)^n(pi/4)
b)n(pi)- (-1)^n(pi/6)
c)n(pi)+ (-1)^n(pi/3)
d)none
for all n belongs to integers

Answer 11

well with the -1/2. You need to look on the circle graph with all of the sin, cos, tan, and cot coordinates. If both of your general solutions are divided by 6 then I would say b. But the equations their I have never seen them that way before.

Answer 12

i had marked the ans as b)

Answer 13

Thats great! I believe it will be tahat

Answer 14

I think it will be that one. It goes with my gerneal solutions that i found

Answer 15

please reply i am closing the question so that i can ask more

Answer 16

ooooooook

Answer 17

i am confused in d)none or b)