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Find the Laplace transform of the function: f(t) =Sin 2t if π ≤ t ≤ 2π; f(t) = 0 if t <π or if t>2π
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Rewrite using the unit step functions.
So, we have: \[ F(s)=\int_{0}^\infty e^{-st}\sin(t)\;dt \]For \(t\in [\pi, 2\pi]\) And, we have: \[ F(s)=0 \]For \(t\in \mathbb{R}\setminus [\pi, 2\pi]\) Evaluate this case to receive the answer.
I'm still having a hard time. I just started learning this material last Friday.
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