no need to spy on my questions
Note that: \[ z-x=200\implies\\ x=200+x \]And: \[ x+y+z=P \]Where P is the maximized variable in question. So we have, with substitutions: \[ x+y+z=201+z=201+200+x=401+x \]But, since \(x<y\), then, we have \[ x\le 100 \]Thus, if \(x=100\) we have maximized \(P\), which is: \[ P=401+100=501 \]Hence, we are done.
(For the above, I substituted \(x+y=201\) in \(x+y+z\) as \((x+y)+z=201+z\). Sorry, should have cleared that up.
Is this copied from brilliant.org?
The question or the answer? I've actually never heard of the site.
the question :-p
Seems pretty interesting, never been, but I'll check it out.
Yep, it must be! The only hits I'm getting are from questions all posted today. @Luis_Rivera you REALLY should not cheat on brilliant.org questions as it violates the rules. Delete this question.
This is not a "riddle" to entertain us, this is you asking people to do your questions on brilliant.org so you can gain points unfairly....
lol
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