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Mathematics 10 Online
OpenStudy (anonymous):

no need to spy on my questions

OpenStudy (anonymous):

Note that: \[ z-x=200\implies\\ x=200+x \]And: \[ x+y+z=P \]Where P is the maximized variable in question. So we have, with substitutions: \[ x+y+z=201+z=201+200+x=401+x \]But, since \(x<y\), then, we have \[ x\le 100 \]Thus, if \(x=100\) we have maximized \(P\), which is: \[ P=401+100=501 \]Hence, we are done.

OpenStudy (anonymous):

(For the above, I substituted \(x+y=201\) in \(x+y+z\) as \((x+y)+z=201+z\). Sorry, should have cleared that up.

OpenStudy (anonymous):

Is this copied from brilliant.org?

OpenStudy (anonymous):

The question or the answer? I've actually never heard of the site.

OpenStudy (anonymous):

the question :-p

OpenStudy (anonymous):

Seems pretty interesting, never been, but I'll check it out.

OpenStudy (anonymous):

Yep, it must be! The only hits I'm getting are from questions all posted today. @Luis_Rivera you REALLY should not cheat on brilliant.org questions as it violates the rules. Delete this question.

OpenStudy (anonymous):

This is not a "riddle" to entertain us, this is you asking people to do your questions on brilliant.org so you can gain points unfairly....

OpenStudy (anonymous):

lol

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