Question

find an equation for tangent line to y=f(x) at the specified point.
f(x)=xe^(-x) where x=0

Answer 1

tangent is dy/dx

Answer 2

what are the step into finding the answer?

Answer 3

take the derivative of xe^(-x) and then put x=0

Answer 4

derivative
=-e^(-x) (-1+x)
=-e^(-0)(-1+(0))
=1

Answer 5

yes

Answer 6

so the equation for tangent line is y=x

Answer 7

why its y=x? you found 1

Answer 8

the book answer is y=x, im guessing where y=mx+b so y=1(x)

Answer 9

yes its y-a=mx+b and you are taking the tangent at (0,0) so a,b=0 and the slope m=1 so its y=x sorry for answer before

Answer 10

thanks for the help