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Determine two pairs of polar coordinates for the point (2, -2) with 0° ≤ θ < 360°.
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x = rcos theta = 2 y = r sin theta = -2 x^2 + y^2 = r^2 ---> r^2 = 8 ---> r = sqr (8) = 2sqr(2) now back to x = rcos theta = 2sqr(2)cos theta= 2----> cos theta = 1/sqr (2) ---> theta = pi/ 4 you have r, theta, plug into formula to get x = 2sqr(2) cos (pi/4) y = 2sqr(2) sin (pi/4) DONE
wait.. so whats the answer? im sorry
the last 2 sentences
the answer choices are; (2√2, 225degree), -2√2, 45deg) (2√2, 135degree), -2√2, 315deg) (2√2, 315degree), -2√2, 135deg) (2√2, 45degree), -2√2, 225deg)
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