Question

Help.

Answer 1

12x^2 - 147

Answer 2

@ParthKohli

Answer 3

Seems like you can't do much with it, but you still can.

Answer 4

\[12x^2 = (3 \times 2^2)x^2\]and\[147 = (3\times 7^2)\]So you have\[(2x\sqrt{3})^2 - (7\sqrt{3})^2 \]

Answer 5

Now if you ask me, it's not a proper way of factoring with irrational coefficients. But if you do want to, go ahead.

Answer 6

is there another way?

Answer 7

That's the only way :-|

Answer 8

and based on your way what would you say is the answer? BTW i know the answer so yeah.

Answer 9

\[(2x\sqrt{3} + 7\sqrt{3}) (2x\sqrt{3} - 7\sqrt 3)\]\[= \left((2x + 7)\sqrt{3}\right)\left((2x - 7)\sqrt{3}\right)\]\[= 3(2x + 7)(2x - 7)\]lol wait

Answer 10

I have another method

Answer 11

Factor out a 3

Answer 12

That's it, just factor out a 3. I was making things too complicated. Sorry

Answer 13

\[3(4x^2 - 49) = 3\left((2x + 7)(2x - 7)\right) = 3(2x + 7)(2x - 7)\]

Answer 14

I'm sorry again :-(

Answer 15

ok got it :)

thank you :D

Answer 16

yeah i did that method since it was easier, i was like @ParthKohli said there was no other option :/ lol

Answer 17

Sorry haha

Answer 18

thank you once again :D

Answer 19

Heh

Answer 20

your a big help.

Answer 21

:-)