Mathematics
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OpenStudy (anonymous):
State the slope and the y-intercept for the graph of each equation.
1. y = x + 9
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OpenStudy (anonymous):
Take the equation of a line in the form
y = mx + b
where m is the slope and b is the y value of the y-intercept. What do you get for m and b?
OpenStudy (anonymous):
m = 0?
and the b is 9 right?
OpenStudy (anonymous):
b is 9, yeah
OpenStudy (anonymous):
but if m were 0 then you would have
0x = 0
OpenStudy (anonymous):
you can look at x as 1x
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OpenStudy (anonymous):
oh. I don't remember how to get the m
OpenStudy (anonymous):
would b be (0,9) ? because we have to graph the points too
OpenStudy (anonymous):
yeah--for the y-intercept x will always be 0. good job
OpenStudy (anonymous):
m comes out to 1 because, substituting back into y=mx+b,
y = 1*x + 9
gives
y= x + 9
which is what we wanted
OpenStudy (anonymous):
so the y-intercept is (0, 9), and the slope is 1
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OpenStudy (anonymous):
yay thank you! so m = ( 0, 1)
OpenStudy (anonymous):
I mean 1, 0
OpenStudy (anonymous):
m is just the slope, not a point
OpenStudy (anonymous):
so the slope and m are just 1
OpenStudy (anonymous):
How do i graph it? Do I just go up 1?
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OpenStudy (anonymous):
Like up 9 and 1 to the right?
OpenStudy (anonymous):
1 can be rewritten as 1/1, so taking that as rise/run, you go over 1 and up 1, over 1 and up 1, etc. from the point (0, 9)
OpenStudy (anonymous):
ohhh ok! can you help me with the next one?
OpenStudy (anonymous):
Your graph for the first one will look like this
OpenStudy (anonymous):
yep it does :)
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OpenStudy (anonymous):
y = 2x - 5
OpenStudy (anonymous):
y = 2x - 5
-2x
OpenStudy (anonymous):
Now Im stuck
OpenStudy (anonymous):
@cholo71796