Question

factor by grouping 4x^2y+5xy^2+y^3

Answer 1

\[4x ^{2}y+5xy ^{2}+y ^{3}\]

Answer 2

Can you reduce it any more?

Answer 3

\[y(4x ^{2}+5x+y ^{2}\]

Answer 4

)***

Answer 5

Okay, now factor what is inside your parenthesis. \[y(y^{2}+5xy+4x^{2})\]

Answer 6

\[y(y+5x+4x ^{2})\]...?

ifeel as if that might not be right but idk

Answer 7

Inside you have \[y^{2}+5xy+4x^{2}\]
So starting with the outside terms you begin with
(y+ )(y+ )

Answer 8

So how would you "get" 4x^2?

Answer 9

2*2

Answer 10

2x*2x

Answer 11

What other way can you get the same answer?

Answer 12

4*x...?

Answer 13

Right, so since you are using the identity a2 + 2ab + b2 = (a+b)(a+b), you can try one and expand it to see if you got the right one.

Answer 14

okay... so after i get \[y(4x ^{2}+5x+y ^{2}) \it then goes \to y(y+5x+4x ^{2}\]...?

Answer 15

No, you cannot factor out another y because every term does not contain one.

Answer 16

\[4x ^{2}y+5xy ^{2}+y ^{3} \rightarrow y(y^{2}+5xy+4x^{2})\rightarrow y((y+\space\space )(y+\space\space ))\]

Answer 17

okay let me see what i figure out

Answer 18

(y+4)(y+x)

Answer 19

Yes, though I assume you forgot the other x. (y+4x)(y+x)

Answer 20

yes i did so then it would be \[y((y+4x)(y+x)\])

Answer 21

Exactly, good job.

Answer 22

thanks eSpeX