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indefinite integals
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\[\int\limits_{}^{}\frac{ 4dx }{ xIn(5x) }\]
Ok, first off, take out the 5. It has no bearing on the integral.
\[=4\int\limits_{}^{}\frac{ dx }{ x \ln 5x }\]
ok. do i need du and u?
Yes, we will get to those next.
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why its 4 in the front?
As I mentioned in the first post, it has no bearing on the integral, so just take it out.
The only terms which you are going to focus on are the ln 5x and the x in front of it.
So, what is your u going to equal?
I see. Equa;?
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*equal?
What is u?
U=XInx?
no, the x by itself is part of the derivative. If u=ln 5x, du= (1/5x)5dx=(1/x)dx
so U is always the whole number of numetator?
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and why dx=(1/5x)?
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