PLease help!

Question

PLease help!

anonymous · Answer

definite intergals 

$$\int\limits_{}^{}  \frac{ x^{3} }{ x^{4}+6 }$$

anonymous · Answer

dx in the end

anonymous · Answer

@abb0t  please help!

abb0t · Answer

Ok. Do you have an idea where to begin?

anonymous · Answer

I need to find out du and u?

abb0t · Answer

Yeah. Well, the denominator is the main problem. But you can could start by completing the square

abb0t · Answer

add and subtract $2x^2$ to both sides to complete the square.

anonymous · Answer

$$\int\limits_{}^{}x^{3}/x^{4}+x^{3}6?$$

abb0t · Answer

What you want to essentually get is something in this form: $$\frac{ 1 }{ (a^2+b^2)^2 - 6}$$ so that you can use partial fraction decompisition

abb0t · Answer

I am guessing that's the route this problem is asking for. Which is a long problem. But I have to go, so if no one has answered this later, I will come back to it. I will tag some people who are very capable of answering this and explaining better than I

@tkhunny @amistre64 @wio

anonymous · Answer

ok thank you

tkhunny · Answer

??  $u = x^{4} + 6$

amistre64 · Answer

like tk alludes to;  the top is essentially the derivative of the bottom.  just multiply by 4/4 and log it back up