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Mathematics 6 Online
OpenStudy (anonymous):

2x^2+15x=0

OpenStudy (anonymous):

This has no solution for x. You're squaring x, so you won't get a negative number to cancel out for 15.

OpenStudy (anonymous):

Oops

OpenStudy (anonymous):

Does that make sense?

OpenStudy (anonymous):

I forgot to add the x after 15.

OpenStudy (anonymous):

Okay....now that makes sense! First, move the 15x to the other side.

OpenStudy (anonymous):

Alright

OpenStudy (anonymous):

2x^2=15x

OpenStudy (mertsj):

Leave the equation as it is and factor out x.

OpenStudy (anonymous):

Remember, to move it to the other side, you need to subtract 15x from both sides.

OpenStudy (mertsj):

x(2x+15)=0

OpenStudy (mertsj):

Now use the fact that if the product of factors is 0, one of the factors has to be 0 and write:

OpenStudy (mertsj):

\[x=0; or; 2x+15=0\]

OpenStudy (mertsj):

Solve each part.

OpenStudy (anonymous):

Did you get all that birdybird?

OpenStudy (anonymous):

I think so...

OpenStudy (anonymous):

Try doing the problem, and tell me what you get for x.

OpenStudy (anonymous):

Well I factored out the x first and got 'x(2x+15)=0' Then I solved for x. '2x+15=0' And I got (0, 15/2)

OpenStudy (anonymous):

You got x = 0 and 15/2?

OpenStudy (anonymous):

Yes. Is that incorrect?

OpenStudy (anonymous):

0 is right. What happens when you plug in 15/2 for x in 2x + 15?

OpenStudy (mertsj):

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