Mathematics
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OpenStudy (anonymous):
2x^2+15x=0
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OpenStudy (anonymous):
This has no solution for x. You're squaring x, so you won't get a negative number to cancel out for 15.
OpenStudy (anonymous):
Oops
OpenStudy (anonymous):
Does that make sense?
OpenStudy (anonymous):
I forgot to add the x after 15.
OpenStudy (anonymous):
Okay....now that makes sense!
First, move the 15x to the other side.
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OpenStudy (anonymous):
Alright
OpenStudy (anonymous):
2x^2=15x
OpenStudy (mertsj):
Leave the equation as it is and factor out x.
OpenStudy (anonymous):
Remember, to move it to the other side, you need to subtract 15x from both sides.
OpenStudy (mertsj):
x(2x+15)=0
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OpenStudy (mertsj):
Now use the fact that if the product of factors is 0, one of the factors has to be 0 and write:
OpenStudy (mertsj):
\[x=0; or; 2x+15=0\]
OpenStudy (mertsj):
Solve each part.
OpenStudy (anonymous):
Did you get all that birdybird?
OpenStudy (anonymous):
I think so...
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OpenStudy (anonymous):
Try doing the problem, and tell me what you get for x.
OpenStudy (anonymous):
Well I factored out the x first and got 'x(2x+15)=0' Then I solved for x. '2x+15=0' And I got (0, 15/2)
OpenStudy (anonymous):
You got x = 0 and 15/2?
OpenStudy (anonymous):
Yes. Is that incorrect?
OpenStudy (anonymous):
0 is right. What happens when you plug in 15/2 for x in 2x + 15?
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OpenStudy (mertsj):
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